wt abt molar mass? @Anmol_Seth
Its just the comparison given that molar mass will be less than actual molar mass.. Which is correct in your case.. @Silla_Priyadarshni
can u upload the sol plz.. i wanna see it..!
if observed/actual is coming to be greater than less than 1 then how vont hoff factor be greater than 1..??
for molar mass i=calculated/observed..
Wait I'm uploading solution
yes i got it... i=calculated/observed
let me know if u need any ans to the questions @Anmol_Seth
I need it for 17 only..
Actually i referred to the answer key of some other excercise that was just a page before the actual answer key ..
My answers that i have tick marked are correct..
So i dont answers for those questions that i had uploaded before this Q17th.. @Silla_Priyadarshni
By logic we can say that increasing the moles of a non volatile solute should decrease the vapour pressure, so the answer should be 200mm Hg for q.25
Any numerically derived solution??
Sry I'm not able to solve it, BTW did you make the eqns etc.?
And in q. reason s the correct explanation of assertion.
You mean Q8 right?? @centarsirius
Its 2.. A is correct, R is correct but R is not the correct explanation @centarsirius
How? Isotonic solutions have same osmotic pressure, so concentration of 1 = concentration of 2, let the volume be same, them M1 x i1 = M2 x i2
I'm clueless why it is given 2
Solution of q.25
=> Pa=(4/7)*350= 200!