I think the products Should be :
Have it checked..
Got it bro.. maine fir se conjugation ki bja di thi
How is acetone helpful in distinguishing between the given compounds??
Option 4 for Q8??
Q-25. Option 2
Yes.. I need mechanism along with answer..
In Q25 why (1) is not the major product??
For Q18-rate of dehydration depends on stability of carbonation form during reaction.
Btw Where is Q5??
Is it option 2 for Q21 @Anmol_Seth
Typological error thi vo.. It was Q25.. Not 5.
For Q18 I'm just clueless
I just read that ortho-nitro benzoic acid is more acidic than para-nitro benzoic acid, doesnt H bonding hinder the acidic effect in the ortho form of the acid??
When it comes to acidity, stability of the counter-ion is one of the main considerations. The nitro-group acts to stabilize the negative charge of the resulting nitrobenzoate by pulling the negative charge onto itself.
In the case of 2-nitrobenzoic acid, it is much nearer and therefore able to more effectively 'remove' the negative charge from the carboxylate group. In the case of 4-nitrobenzoic acid, it's still able to do so but less effectively as it is further away.
The hydrogen bonding effect that you describe does exist in 2-nitrobenzoic acid but this does not act to make it less acidic. While one might reason that the hydrogen bonding "holds the proton in place" and therefore makes it harder to leave, the presence of the hydrogen also means that both the nitro and the carboxylate group are highly unlikely to be simultaneously coplanar with the benzene ring . The energetics in this case are likely to favor the release of H+ in exchange for a coplanar configuration.
Any doubts, do let me know
Got it..thank you sir!!
@ananda_krishnan @aayush please help me out!!
Which Question (s)??
All those for which you can provide solution.. Upr ke jitne hai sb me se...
Referring to post 4
The answer for question 24 is option 2
Because generally speaking the alcohols have more Hydrogen bonds when compared to the corresponding ether causing higher boiling point to alcohol, and as ethers have atleast some form of hydrogen bonding in them, when compared to alkanes which have purely Wandervaal forces of attraction as a binding force, ethers have higher boining point when compared to alkanes. So the answer would be alkane which is option 2
Its option 2 for Q24 @Tarun_Gudipati