%mass=15, d=1.19, MM=98
Sir what if we do with normal method
Sir we have to calculate molality
Upload the picture of your solution.
Yes, i have calculated molality by using molarity.
Sir can you tell what is wrong in it
Sir can you tell my mistake
See, you have to write no of moles of H2SO4, and you are just writing it's given weight.
Also, you have assumed the volume to 1000cc, so all your calculation should be based on that only.
The weight will be 150, instead of 15.
Sir I am having doubt that what should we take moles in this type of problems .
What should moles be taken when it comes concentration in m/m or other
see, no point of confusion here.
You have calculated everything by taking 1000cc as basis.
So take weight to be 150, so moles will be 150/98
OK sir now understood
Sir but how we will calculate moles if it is given that h2so4 15%v/v
That means, 15 ml of h2so4 in 85 ml of water.
Now calculate the weight of the solution by using density.
Weight of 85 ml of water will be 85 grm as, density is 1gm/ml for water.
So calculate weight of h2so4 accordingnly.
Sir one last doubt that 18ml water is 1 mole .??
But only if the density is 1gm/ml, because density is a function of temperature.
What is the answer @Sushant_Kumar_Mishra
Take radius as 3×10^-8 cm
Calculate volume of one virus(4/3π r^3)
3.calculate mass by volume × density.