The 2 chiral carbon and double bond will give total 8 out of which only 1 will be optically inactive.
Can someone confirm if this a right method or is there any better method?
Still I was scared when I saw the question. Can't remember any formula hope they don't ask too difficult.
Even the structure of the compound looks creepy
Got it .
Thanks a lot @Ayan_Agrawal @Shantanu_Thakur