How many optical isomers possible for this compound?

how to calculate it ?

Two ki power n minus one

@Raghudevram_Singh @Supreeta_Sen
How to count without formula

You’ll have to write individual configurations like
RRRR
SSSS
RSRS
RRRS etcetc and see which ones are optically active

Will take a whole lot of time, ig

3 R and 1 S will any be inactive?
@Supreeta_Sen

Nope don’t think so

@Supreeta_Sen
Try counting method. Answer doesn't match I guess.
The case in which there are 2R and 2S will have miso compounds. But the others?

I actually had tried this, and I was getting more than 8 :woman_facepalming:t2:

I thought maybe you’d get it :sweat_smile:
I’ll try it again some time later

Same. 10 or 12 I guess.

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When does this formula exactly work and not work?
Do you have any notes on this part?

@Chirag_Hegde
When there is any symmetry

@Chirag_Hegde @arush_kumar_singh @Supreeta_Sen @Raghudevram_Singh
Guys, can you please try without formula but normal counting method?

And when there isn't tab 2^n?
@arush_kumar_singh


Lol paper khatam ho jayega but I won't get by counting

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Yeah that’s correct

And when doesn't this formula work?
When there are more than 1 POS?

What’s wrong with one POS only? Even then it won’t work na?

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I’m getting 12 by counting which means some of the 12 I’ve counted are optically in active. Can someone say which one?

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I don’t think they’re going to be optically inactive.
I think some of them are identical.

Ahhh. Forgot this completely.

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