Because 3 mein bhayankar resonance hai that means e- jo hai wo dene ke lie available nahi hai which implies less basic. III mein 2 resonance hai and II mein 1 resonance @ruchi
but in 3 e of co are in resonance not the e of nh2, so isn't there cross conjugation on co?
To wahi to kaha meine ki CO bhi e- le rha hai and ring bhi le rhi hai. TO WO DEGA KYA? THATS WHY LESS BASIC @ruchi
ring nahi le raha infact ring co ko de raha h so co ko both ring and nh2 de rhe h right??
Actually leta deta koi nhi hai charge is distributed in all main thing is that. So less for N. Distribution leads to increase in acidity and decrease in basicity.
but nh2 ke e ring me thode n distribute honge?
Nhi Honge. I misinterpreted sorry @ruchi
but wo benzylic position pe nahi h na? there should be only 1 sigma bond bw nh2 and ring for that
Why is 3 more basic then?
Actually CO NH2 se lega. None else. @ruchi
Earlier I didnt see that conjugation is absent.
Final verdict - II is more basic because usmein +ve inductive of Ch3 is also working. Which reduces charge distribution. @ruchi
Got it @ruchi?
@ruchi u can also see as both have Co so don't check them, so we r left with ch3(+I) and phenyl (-i) so ch3 causes more basic nature
Phenyl not showing +m @Azimuddin_Sheikh
so is +i of ch3 stronger than cross conjugation of co by the ring?
@aayush bro phenyl show +m but as there is electron withdrawing group attached so less chances of showing that, thats why (-i wins).
co will have lesser e withdrawing effect on nh2 in 3 than 2 due to conjugation from ring, making it more basic than 2, but 2 will +i so will +i dominate over reduced e withdrawing effect of co?
@ruchi u r not considering -i effect of phenyl too (it will destabilise nh3+) so then II would be more basic than iii. By Compairing only +I and -i we can say this. Cross conjugation will cause just less chances of double bond in o to get closer to nh3+ . Hope u got that?