Bro why is the order of stability this:
More -I of O makes the carbocation more electron deficient.
1st should be more acidic
Another method is to check the stability of the conjugate acid after removing H+
Why para one is more stable?
After removing H+ ?
-I effect reason is simple
Oh yeah thx bro, sry for typing wrong
@Anindya_Sikdar @pratyaksh_tyagi @Viraj bro compare basic strength in these three cases, and the reason why too :
3>1>2? For 1st
Last one has 2 more basic as lp delocalisation is less than 1
@Anindya_Sikdar bro given order 2>1>3 .
Yes 2>1>3 for 1st @Azimuddin_Sheikh
@pratyaksh_tyagi Bro ans given is 1>2 For last. And how for first 213? @pratyaksh_tyagi Bro
For first compare stability by adding H+ to minus charge. In CF3 carbon will bear positive charge
I thought cf3 is a strong ewg. So it will decrease e density at ortho and para pos. Hence 2 is most stable. 1 should be less stable due to lower -I effect and 3 should be least stable as it has relatively higher e density at the -ve charge.
Ortho has more -I of Cf3.meta is not directly involved in resonance with -I've charge , whereas para and ortho are ,
-I adds to stability
Why r u not considering -h effect too? and h effect is more than -i effect
@Azimuddin_Sheikh due to VEry high E.N of F , h effect would take place in CH3. Not in CF3
@swetank_sahai From your method i got that 3 is least basic , pls can u compare between 2 and 1?
In second image b should be more basic as +I effect of Ch3