Correct! Show me the mechanism @fog856
The alkynide ion forms and then the OH-,
alkynide ion is better base, attacks the first compound...so O- can only attack the primary alcohol
Finally with Lindlarg catalyst we have cis saturation of alkynes to alkenes
For first one, is the answer B?
76, is it B?
I feel 36 should be C.
I feel it's D for last one.
What will be the order @Churchil_Dwivedi
47. I think it should be C as the equivalent resonance structure overpower the extensive resonance of phenoxide ions. The same reason why acid are more acidic than phenols.
More resonance= Less charge density=Less Nucleophillic
36 is not B @Churchil_Dwivedi @vishwesh_kumar .
Its C @Unik-Wadhwani bhai is correct
47 its C
76 B correct @churchil_dwivedi
Bhai Dono products milenge in 36. Depending on cis and trans.
In question it is only cis given @Churchil_Dwivedi
76 B kaise?
76 mein toh elimination ho jaayega. Tertiary halide hai na. Toh alkene banega. Haan 36 mein my bad it's cis so C is correct.
Here it :
Extra marks for good handwriting @Aayush
Can you pls solve 47
My mind says ii>iii>i but option not given @fog856 @Sarmila @Praveen_Venkatesh
For 47 it should be D in my opinion because there the word is : PROTIC SOLVENT. So in that case, the best Nucleophile will be the one which undergoes least extent of solvation.
Answer given is c. @Churchil_Dwivedi
@Mayank_Chowdhary whats your reason for C option in q 47 ?
@Anmol_Agarwal more resonance to (i) mein hai to (i) to least nucleophilic hona chahie.
@aayush That is what i have explained.Why it wouldn't be 1 but 3
@Anmol_Agarwal i didnot get what you mean by equivalent reso structure overpowers