Please solve this question
Please confirm the answer.
Shud we assume no repetition @Manan_Upadhyay ?
Coz otherwise ∞ possiblties will be there imo.
@Viraj in a set the elements are never repeated
The answer for 1st is 3^5 and 5×3^4 for second. I got it now .
Oh.yup had forgotten that.
Every element has 3 choice
Go to P , go to Q , neither in p nor in Q
4 element has 3 choice and 1 has to go to P and Q whose selection will be ^5C_1
Yup this is the approach. Sometimes simple things look complicated!