ANS- 1) Order of hydrolysis=Polarity of C=O, EWG enhances Polarity
ANS- 4) N factor of SO3(2-)=2; N factor of KMnO4=5
ANS- 2) Boron has a vacant P orbital and no back bonding has yet been achieved as C has no l.p.e
Rest all are Lewis Bases anyways
ANS- 1) Fact (59,27)Co + n → (60,27)Co. It further Beta decays to Ni but not important.
ANS- 2) Advised to be learned as a fact as it is explained via CFSE theory involving t2g and eg orbital and is long AF
ANS- 3) I hope it is clear that Cl>F and S>O due to e-e repulsions. For F and S refer NCERT as these can't be compared easily and need to be learned.
ANS- 3) Draw the structure and you'll see only lp-lp are minimized. lp-bp could further be minimized if l.p were on axial position but they aren't.
P.S.Qus 32 ke upar khoon na bahao!