Example 1 :
A 60cm guitar string under a tension of 50 N has a mass per unit length of 0.1 g/cm . What is the highest resonance frequency of the string that can be heard by a person able to hear frequencies upto 20,000 Hz?
Ans: 20 kHz
isme pucha kya hai
aur itna data q diya hai
Fundamental frequency = v/2l , ab iska integral multiple will be the frequencies heard by person .
Ooo ye toh maine socha hi nhi
n ki value integer honi chahiye
Same question came in a chaptest that I wrote 2 days ago. First calculate velocity. Then find n by using giving frequency and substituting in F= NV/2l
Same approach na @pratyaksh_tyagi bhaiya?
Actually my question had options which differed by 2 decimal places. So this question was RIP.