i doubt the given answer to be wrong. Can anyone plz check. ..
That's correct bro.
It’s correct !
To find it’s range you can write it as y= 3- 8/3-t²
Now you’ll get the desired range
This is my rough work, plz check where I'm wrong And
Your method as well as calculation is correct , even answer will come out to be same
Acc to case 1 take intersection of y<1/3 and y<3
Which is y<1/3
Acc to case 2 take intersection of y>1/3 and y>3
Which is y>3
And hence solution is union of case 1 and case 2
Which is y>3 or y<1/3
Ohh... I was blank after I made the cases and I stopped there . Btw thank you bro....