i doubt the given answer to be wrong. Can anyone plz check. ..

# Doubt from trigonometry

That's correct bro.

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It’s correct !

To find it’s range you can write it as y= 3- 8/3-t²

Now you’ll get the desired range

This is my rough work, plz check where I'm wrong And

@Samarth_2020

Your method as well as calculation is correct , even answer will come out to be same

Acc to case 1 take intersection of y<1/3 and y<3

Which is **y<1/3**

Acc to case 2 take intersection of y>1/3 and y>3

Which is **y>3**

And hence solution is union of case 1 and case 2

Which is **y>3 or y<1/3**

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Ohh... I was blank after I made the cases and I stopped there . Btw thank you bro....

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You’re welcome