In question 1 i got order as 5>3>2>4>1 but in answer key mentions 5>4>3>2>1 why
In 2 and 3. There are methyl groups on both the double bonded carbons. Due to the +I nature of methyl group. It destabilises the negative charge caused due to hyperconjugation on the other carbon. Like:
Also.. another explanation could be equivalent resonance structures in the case of 4 which causes more stability.
Is 4. d?
No answer key says option A
I guess I was considering hyperconjugative structures.
If you take each carbocation separately, in (A) the +ve charge will undergo resonance and a positive charge will be induced in the tertiary carbon. In (D) +ve charge is induced in a secondary carbon and hence less stable.
Is it d for 5th one?
- In D, there is +I effect from methyl group. Also.. the two double bonds in the ring stabilize the positive charge by undergoing conjugation.
For 5th it should be D because of more conjugation than any other molecule