Can someone explain what the underlined text means?
Reference: Class XII Chemistry NCERT, Part 1, Page 50
@Chirag_Hegde @pratyaksh_tyagi @Supreeta_Sen @Azimuddin_Sheikh @Mayank_Chowdhary
as it is in the case of dynamic equilibrium of liquid and gas
the statement state that solid has vapour pressure and it is equal to that of liquid
for boiling point vapour pressure is equal to that of atm pressure
Why is it so? Can you explain a bit more in the case of freezing?
I am not able to understand what vapour pressure of a solid means.
even i dont know
once we were asked about it no one knew
I guess it's similar to liquids have vapour pressure some kind of sublimation?
Bro if there in no equilibrium there will be formation of vapor from liquid due energy from surrounding
Vapour pressure is kind of like the pressure exerted by sublimation of solid part. Its value is very low . So the line actually means the temperature at which rate of sublimation is equal to rate of evaporation from liquid part . it can be very much more well explained in terms of chemical potential but that's also beyond syllabus likely.
Adding to what @Azimuddin_Sheikh said https://en.wikipedia.org/wiki/Vapor_pressure
Read about the solids part and the introduction part
For the solid-liquid equilibria the vapour pressure of both of them must be equal.
Solid equilibrium vapour pressure is the pressure when the rate if sublimation is equal to that of the depositing of the vapour back into the solid
How did they compare CH3CN and CH3OH?
@Supreeta_Sen @Azimuddin_Sheikh @pratyaksh_tyagi @Yash_Srivastava2 @Chirag_Hegde
Like dissolve like. Non polar dissolve non polar, polar dissolve polar. So for a non polar solvent, less the polar, more the solubility.
I meant to ask how do we compare the polarities of CH3OH and CH3CN?
Idk until now I used to see inductive effect, but inductive of CN is mroe than alcohol.
What do you think
The same thing is confusing me as well.
In OH there are 2 lone pairs which contribute to polarity while in CN only 1. So O contributes much more.
Can you try to show it diagrammatically like this?
I am not able to visualise how the electrons on O add to the net dipole moment.