# Doubt from solution

**Akash_2**#3

In this we just have to use vapour pressure of water to be 760 torr,which is atmospheric pressure and then use use p=p° * mole fraction of glucose

So p= 760* (0.1/(10+0.1))

Hence p= 752.4 torr

So p= 760* (0.1/(10+0.1))

Hence p= 752.4 torr