# Doubt from sequence and series

**Hritik_2020**#1

**Hari_Shankar**#11

We have b-a=2(c-b)

If b=ar,c=ar^2 we have after substituting r-1=2r(r-1) \Rightarrow r=\dfrac{1}{2}

Hence \dfrac{a}{c} =4

We have b-a=2(c-b)

If b=ar,c=ar^2 we have after substituting r-1=2r(r-1) \Rightarrow r=\dfrac{1}{2}

Hence \dfrac{a}{c} =4