Directly nahi likha hai sayad but on Page 301 first para of halides class 11 part 2
Ohh . Got it bro thanks
In the boiling method of removing temporary hardness of water, Mg(OH)2 is precipitated.
The reason they give is that its Ksp is higher than MgCO3.
If Ksp is higher doesn't it mean that Mg(OH)2 is more soluble than the carbonate?
Did you understand what he is saying?
Can you explain pls.
Wait I thought you’d get it. I didn’t exactly understand either . Will explain, lemme understand it
@Viraam_Rao bro he’s saying something like
MgOH2 ka Ksp is 4s^3 and MgCO3 ka s^2. So when you find out the value of s, you’ll get a lesser value of s for MgOH2 than MgCO3.
However this sounds really vague and juvenile to me. Not convincing
yeah. kind of a weird comparison
well just remember it as a fact then
Here's my intuition
More ksp = more solubility = more ions = more easily reach saturation = precipitation starts before the ion having less solubility