Doubt from reaction mechanism

a>c>b?

How?

a will become aromatic after 1st step which is very stable
b will become antiaromatic (least stable)

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I got the same but answer is a>b>c
Maybe it's wrong

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Nope a won't become aromatic
For aromaticity we need all sp2 hybridizd carbon and resonance all over the ring.
But yeah a will be more stable than c so order must be a>c>b
I doubt the answer is incorrect

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Oh yeah..
Thanks @Mayank_Chowdhary
a will be more stable due to allylic carbonation right?

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