# Doubt from Quadratic equations

**Shiva_1**#2

The above is the simplest method. The approach behind the problem is to expand the multiplication.

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**Shreyas_2021**#5

Yes, I am also getting 7

z = 3x, y =0

So, 10x^2<=100

So, |x|<3.16

Therefore, x = all integers between -3 and 3, including both of them

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**Gaurav_2020_3**#15

@Shiva_1 Sir , I totally agree with you that it's repeating it's behavior but we can't say that it would not have any root by observation .( May be I am wrong but do you have any example that explains the same case)

**Shiva_1**#16

You can draw two graphs and see that they don't meet. This is another approach which shows logical proof for my answer.

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**Shreyas_2021**#17

Yes, this would be, imo, an easier approach, drawing the the graphs of x^2 + 4x + 3 and -[x].