# Doubt from Quadratic equation

Maximum value of \sin x+\cos x is \sqrt{2}

And Minimum value of y^2-y+a is \displaystyle a-\frac{1}{4}.

So for No real Solution, We have

\displaystyle \Rightarrow a-\frac{1}{4}>\sqrt{2}\Rightarrow a>\sqrt{2}+\frac{1}{4}.

1 Like

**Shreyas_2021**#4

Yess, sorry, i took the numerator as root D instead of D

Thank you @Jagdish_Singh sir