Doubt from Probability

When throwing a fair die, what is the expected value of the number of throws needed to get a
5?
@Sneha_2021

Hint is formation of infinite agp
Will post solution soon

Ans is 6
E(x)=1+2(\frac{5}{6})+3(\frac{5}{6})^2.....\infty
Its generalized equation not only to get 5

1 Like

@Sneha_2021 use \displaystyle in your latex code

deleted