# Doubt from Polynomial

#1

@Sourav_Dey sir , @Mayank_Chowdhary , @Raghudevram_Singh

1 Like
#2
#3

This one also

1 Like
#4

Is it 2010 for the second question ? @Tushar_Rathore

#5

I take my words back 90 is the correct answer
I didn't read that minimum thingy

1 Like
#6

Correct! @Mayank_Chowdhary

#7

Did u get first one bro ?

#8

@Mayank_Chowdhary @Tushar_Rathore
Why do we want the series to be repeating. Not getting this part?

#9

Nope trying
Just solved till here
513=a+2b+3c+4d
4745=a+16b+81c+256d
and we need to find min of (a+4b+9c+16d)
Had the series not been repeating then we would at some point get a fraction
If we had a increasing or decreasing series we would at some point get a fraction @Viraam_Rao

#10

Bro, why does a,b,c,d have to be the same for S1 and S4.
Like can't
4745 = h + 15 f + 81 g + 256 m

#11

a_i would be fixed right ?

2 Likes
#12

Because the order of the a's doesn't matter, we simply need to find the number of 1s 2s 3s and 4s that minimize S_2.
@Viraam_Rao

1 Like
#13

@Jagdish_Singh @Hari_Shankar @Sourav_Dey
SIr pls help

#14

@Sourav_Dey sir , @Tanmay_1 sir

#15

@Tushar_2019 what is the answer of the first question ?

1 Like
#16

correct answer is 905 @Mayank_2019_1 bro

#17

I'm getting 911.
Is there any chance of wrong answer?

#18

Depends on ur solution @Abhishek_2021_2