# Doubt from pH calculation

Can we do in this that Na3PO4 is neutral ,so we will directly use NaH2PO4 direcltly for

Ph = -log[h+]

Ph=-log0.2

Can we do this , i am confused that what is the use of ka1 ,ka2etc

These are amphiprotic ions so we cannot do it directly ..I will try this if I get I send.

Formula to do this kind of q

@Samarth_2020 @Sneha_2021 can you guys try this

Answer?

Answer is 9