OK a simple question what is the probability that an equilateral triangle can be inscribed in a circle with all its vertices on the circle.
I know practically it is always possible to construct an equilateral triangle inscribed in circle but guess what the probability still comes out to be 0. So why is it so? It's because of the infinite other ways to inscribe a non equilateral triangle in a circle.
In our case too we practically can cut a right triangle anyhow and it is pretty evident from graph too because we got all the points on line A+B=90 as solutions to our condition. It's just that the number of solutions of our condition are negligibly small as compared to measure of universal set.