For the second question,
Its way more than you would think.
Its six times as strong as strong as a single bond
Is it only factual...
Or we can make guess by some property
Is for first ans is P ? @arush_kumar_singh
N is more e- -ve...
It don't form dpi bonds @arush_kumar_singh ( don't have d orbital)
Well first N doesn't form pπ-dπ bonds
Second, the bond strength increases as distance from nucleus decreases. Bond forming orbitals of P are closest to nucleus because of smaller size. Hence answer should be P.
I m bit confused in pπ - dπ bonding..
In Ncl3 pitrigan can form back bonding..
Which type of bonding is this????
@arush_kumar_singh wait bro I'll tell you the reason. I have to do some searching for this. Can you once confirm the answer from the key? Is it P?
@Azimuddin_Sheikh did you see that Bro? What about NCl3? N forms pπ-dπ bonds there no? Could you explain?
Didi mai bhi wahi soch rha hu , aisa kyu hota hai .
Ya P is given
Well I made the same mistake as you did and hence I just took it as a fact. If there be anything worth knowing in this arena, I would be more than delighted to be enlightened.