# Doubt from mechanics

Is the answer A

Yes...but the total time of flight is 2 sec...how is radius of curvature possible after that??

How did you find time of flight as neither height of cliff is not given nor the distance where it hits the surface

You have calculated the time when it will come back to a point parallel to cliff(from where it launched) ,there will be one more time that is required to cover height of cliff

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Yeah I realised that..thanks bro

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for all kind of radius of curvature questions

use

((1+((dy/dx)^2))^(3/2))/(d^2(x)/((dy)^2))

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