Since in Perpendicular magnetic field charge moves in a circular path of radius = mv/qB so here in 1first case where d=mv/qB it will form a quarter circle hence final velocity will me at 90° from initial
Q 39) b and c
Bro didn't understand ur approach @Tushar_Rathore
In which qn or part bro
Vt = d ???
From Newton second equation s= ut + at²/2 here a=0
D=V(x)t in x direction..
Why is the acc 0 in x direction?
Because there is no force in x direction. Force due to qv×B acts in y direction.
And solution for Q42 (Requires mostly use of calculators)
@Mayank_Agarwal @Tushar_Rathore @Mayank_Chowdhary