How many different products will be formed from Kolbe's Electrolysis of CH3COOK and C2H5COOK? The answer given is 7 and it includes 2 kinds of esters and an alkene. But I had learnt that Kolbe's only gives symmetric alkanes. Which one is correct?
This reaction will produce 2 ester and 3 alkenes in which 1 alkene will show cis/trans isomerism, 1 alkene is optically active and 1 ordinary akene. Hence 2 esters+2(cis& trans)+2(R & S)+1=7 products.
But the solution says the 7 products will be:
C2H6, CH4, C2H4, C3H8, C4H10, C2H5COOCH3, CH3COOC2H5