Question no 2 and 3

# Doubt from kinematics

**abhijit_2020**#1

for the question 3:

we have u=10 , \theta = 45

The height of he two hurdles y1=2 and y2=2

Let the distance between the starting point and the first hurdle and second hurdle be x1 and x2 respectively.

we know from the equation of projectile

y=xtan ( \theta )[1 - x/R]

R = u^2 sin2(\theta)/g

**abhijit_2020**#4

But answer key says d is 4.5m and distance from point of projection is 2.75m and both are not matching with your solution

**abhijit_2020**#8

You did everything correct but one thing you didn't realise that root 5 is 2.23 not 2.73

**Mayank_2019_1**#11

For Q.13, we have been given the equation of the projectile.

We know the standard equation : y = xtan(\theta) [1 - \frac{x/R}]

So comparing the given with the above we get R which is the maximum displacement along the x axis for which y axis has zero displacement