Felt question was straightforward until I saw G and H are different.Im confused if we can change configuration or not.
Bhai we have to check GI by substituted cycle. So at least two groups on a cycle must be present and both should be attached to a sp3 carbon.
So I think the answer should be 1( onlyE). Considering both GI and OI.
So specific rotation (1-x)168+(x)112=130.66
None will show GI? The configurations are fixed right?
Answer is given only E