As such we needed incorrect options , so given ans is D only . Can u pls show each diasteromers ? Also I got total optically active 16 , what u get bro if different pls tell how? @Viraam_Rao bro (also pls tell if I am thinking right : there will be three cases of joining of cl, first one at ch3 would give 4 optically active and so 2 pairs of enantiomers , now at ch2 , it will give 8 optically active ,so 4 pairs of enantiomers , and at last at" ch3" join with ch2 , it will give four optically active compounds . so two pairs of enantiomers.) By this thinking I can see if we take first two cases we will get total disastereomers to be 4*8 = 32 , I know I am doing wrong pls tell what part I am getting wrong ?