Yes bro anyone. not striking.
After substituting z= sinx , put 2-z = (2+z)d^2 is it the short method for u ? I did by this
I think this much is trivial to work.
Oh I thought there might be a better substitution or something which I didn't know. Thanks tho
You can write the integral in the form of (cos^3x)/(1+sinx)^3 which will make it very easy since Cos^3x can be written as Cosx(1-sin^x), you can get a algebraic expression if you take sinx=t. Did you do the same?
Hey can you do this on paper? I couldn't catch what you wanted to say
Sure, I'm having dinner atm, it'll be a while.
I've taken Sinx=t as the substitution. After the last step, substitute 1+t=z and there you go!
Didn't get the second line? How did you convert the intial integral into that bro?
Ah, sorry. I've done a shameful calculation mistake. Nevermind about my solution, it's totally wrong!
@Viraam_Rao @Azimuddin_Sheikh @arush_kumar_singh @Raghudevram_Singh
Second one multiply and divide by (x+1)
Then the integral is a common one
Try First one too
First one is unclear to me ,is we have to find definitely integration of hx from 0 to1
yes definite integration of hx from 0 to 1