Neopentane groups are not good electrophiles due to steric reasons.
Why not here Sn1 take place?
Carbocation then rearrangement?
It’s an essential exception. Bro what I’m saying is nucleophile substitution cannot take place coz neopentyl halides are poor electrophiles
See carbonation rearrangement might take place I'm not saying no but first the substitution is not favoured.
Same is applicable for Sn1. They’ve not typed it out. I’ve written this in my notes but not explained properly.
Is this multi or single?
@seshu_ram @Viraam_Rao @Supreeta_Sen @Azimuddin_Sheikh
@seshu_ram single bro, i m doing this book again. so that i dont cheat i marked all ans correct
Is it C?
I gave explanation see that
Is it A?
I don’t understand your doubt. But please confirm the answer.
Yeah its A
Show me ur mech
See bro question is wrong. They should mention 2 mol HBr
But Br, would be much weaker in I- compared to the other halogens. Plus, going with the given carbon atom is secondary.
I didn't read excess😂 question is correct. This is what happens when you solve FIITJEE packages and GMPs😂 you expect every question to be wrong
R u sure about this? I mean for real
It seemed that way to me at first. Don't know if its right or wrong.
Pls confirm about the carbocation formation at secondary or primary.
If i give u similar ques to find stability order of carbocation i doubt u will consider -I effect
Definitely not. Carbocations are not stabilised by -I
Please represent your doubt on paper. I am unable to understand your query.