Q47 shouldn't it be racemic mixture?
Is that not the answer?
Or more like what's the answer given?
Don't tell ans lemme think
Can I now?
Is it A?
I saw the answer
I seem to have marked it very confidently in my book
Now can't remember
@Yash_Srivastava2 yes it is A,why?
U know na its follows free radicle mechn
So 2nd carbon from left will have const R or S
But 1st will be once R and then S so its Diasetriomer not by definition
Bro but doesn’t bromine get substituted on3 degree?
As per @Manan_Upadhyay ‘s notes. He sent today on another thread.
Bro conjugation jada benificial hota hai
And btw where is 3 degree present @seshu_ram
Deuterium attached carbon
Its 2 degree bro
Sorry whatever mistyped in post. But even then it is preferred bro.
I get confused with deuterium. Anyways thanks for correcting.
No bro when conjugation is present forget everything about 2 deg or 3 deg remember this
See the carbon attached to Ph and the one attached to D are both 2°. But benzylic radical is more stable.
Yes got it!
Im unable to understand what you are saying. I think the answer ahould be (d). Can you please elaborate on that?
How D ? D cant be becuz its related to position of bonding bro
I think u r confused with confermer
I was looking at question 48. My bad
Guys which of the following reactions are in JEE portions?
Koi bhi ni