Doubt from hybridization

How to find out hybridization of both (indicated sulphur) from structure @Shwetanshu_2018 @Abhishek_2020_5 @Bhuvanitha_2020 @Samarth_2020

The left S is connected to oxygen (more electronegative atom) through total 5 bonds therefore it has +5
The sulphur in centre is connected only to 2 S i.e there is no electronegativity difference and hence it is having 0 oxidation state

1 Like

Bhaiya thank you for that but I wanted to ask I have written sp3 hybridized in left one but now I have forgot how that came out to be sp3 so bhaiya can u tell me how sp3 have come @Shwetanshu_2018

Bhaiya please see this that's why I want to know how to calculate hybridization of sulphur @Shwetanshu_2018

@Vibhu_2020 for calculating hybridisation from structure i usually used this trick —> number of lone pair + no of atoms attached (not bonds)
IF it comes out to be 4 then Sp³ , if 3 then Sp² and so on

1 Like

Thanks bhiaya

1 Like

1 Like