Actually we should. Real JEE questions are pretty straightforward, especially organic. It will be tough, but simple at the same time
True. As you said, the reaction was given in the paragraph so they are hinting at what they expect.
Has anyone seen complicated GR questions in JEE?
No. Simple straightforward SN reactions only.
My teacher is like, if you ask me, I'll explain that same reaction in a totally opposite way, giving a completely different product, but it will be plausible.
Like kuch bhi explain Kar sakte hai
Also, that Pinacol thing.
I couldn't find it anywhere that Pinacol is trans rearrangement. Is just that statically that sort of migration is favoured?
Yes. @Viraam_Rao in pinacol, irrespective of shifting tendency, you have to shift anti coplanar only
Last yr jee made their own migratory aptitude right...! So i guess we dont need to memorize them
And not given in ncert i guess
In pinacol, migratory group has to be in the trans position to the leaving group. This is what I know bro
@Chirag_Hegde @Supreeta_Sen @Yash_Srivastava2 @Sourav_Kumar
Thanks for inputs everyone
Here, first reaction is Grignard reaction and second is SN2. Answer given is C. I understand that second one won't work, because it's a 3° halide. But even Grignard reactions are governed by steric factors. Why will method 1 work here?
You haven't seen mine yet
Courier to me after you are done photo copying
The attacking species is bulky/hindered and not the site of attack so the reaction will happen easily imo. If it was the other way aeound, elimination would have happened.
Acchhaa okay. Thanks!
Note that i am talking about the second step of method 1 here and elimination won't happen here as such, i was talking abt a general case...but i guess you got what i was trying to say. @Supreeta_Sen
RMgBr can be considered as R- right? So here won't 3 degree anion be too unstable? @Sourav_Kumar @Supreeta_Sen
what's the reason??
I'm not really sure, wait for someone else to say.
This is with reference to Post #20.
Can you clear these doubts:
That’s the electronegativity order of the 4 elements, to decide which metal-carbon bind is the most polar and can easily break.
I really don’t remember bro, I’ll update as soon as I get something
Yes, that reason in the picture is correct.