Doubt from goc

Question no 54 and 5515731470060026468239179982801516

Please confirm these answers
54) e
55) d

image

image

1 Like

Yes correct can you explain me

See the given compound undergo resonance with lone pair of Nitrogen if we consider situations like
C=O bond before resonance it has pure double bond
After resonance it’s double character decrease due pie electron delocalisation.

1 Like

For q54) you can see the structure of each compound in post #3 and it is clearly visible that only cyclohexyl radical doesn’t have resonance hence option e is correct
Q55)
In Ch3CONH2 the CO bond is between single and double bond
Hence it’s weaker than CO bond in CH3COCH3 because here it is double bond
Hence bond length of CO in Ch3CONH2 is greater than bond length of CO in CH3COCH3

1 Like

Question 67 a is answer there are 7 resonating structures but how to draw i am confused 15733865741253648554795185404528

image

Question 7415733879666719071896503020575015

I think it should be A because the left compound has incomplete octate (CH3+) whereas right compound has complete octate

Ya its correct thanks

In option right side compound is forming most stable carbocation (we call it iit carbocation)

Question 76 in this i want to ask one question does +M group decreases or increases the stability of carbocation and what about question 7815735615246866761678343592016050 15735614590717021889570246341416

Most stable carbocation will be B option because after resonance it will octet complete cation.

+M group increases the stability of carbocation

1 Like

For Q76) i think option C should be the answer , and it has max +M effect

Q78 answer will be option A

76 --> c>b>a>d.

1 Like

For q78 it should be option A because carbocation is being stabilise by +H effect and hence H > D > T for +H effect

1 Like