Question 1 why 5th compound will not form geometrical isomer
Please tell anyone
One of the 3 carbon atoms has 2 identical groups (i.e. 2 Cl atoms on the same carbon atom).
So it cannot show geometrical isomerism.
For geometrical isomerism in a ring , the carbon of the ring must be have 2 different substituents attached to it and here same substituent i.e Cl is attached and hence there is no geometric isomerism
For geometrical isomer cis-trans must be forming
But in 5 both the chloride are on Same carbon.
So it will not form cis-trans
What is cis-trans,cis-cis,trans-trans isomerism in geometrical isomers
If suppose there are 2 diff double bonds in a molecule about which geometrical isomerism is possible the usually in questions it is given to identify then cis-cis is written to denote that about 1st double bond it is cis and about second double bond also it is cis and so on
CH2Br must be given more priority over CH3 because Br is heavier than H
Ya i got it after your post 9 ok if i am not mistaken in c part br will have more priority than oh
In c part the competition is not between OH and Br it is between C and Br because towards left 1st C comes and then Oh so 1st compete between C and Br so Br will be given more priority
read cahn in gold priority (CIPsystem) you will know every priority in e and z
for instance molar mass ,atomic number , triple bond most beutiful priority and one more is in cyclic system how priority given..
last is real structure and imaginary structure priority..