Doubt from general organic chemistry

Question no 4,6 and 815727180475345391355440840119501

Please Confirm these answers
4) c
6) b
8) c

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Ch3Mgbr , Ch3-mg(2+)--br

Triple bond is more electronegative than double bond so that’s why in b option phenyl +I first a is simple -I :

For question 8 option C because it has lone pair to donate. So it’s donating group.

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For 6,
CH3 has sp3 C,which is less electronegative than sp2 C of benzene ring, so it show +I effect.
-CCH has sp C ehich is more e.n. than sp2 C, so it shows -I effect.

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Also, Br also has 3 lp, but in case of halogens -I effect dominates over +M effect.

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  1. Option A) Cl is very electronegative and hence it will act as -I group and hence Ch3 will act as +I group

    Option B) No electronegativity difference

    Option C) It is a famous reagent known as grignard reagent , there Mg being a metal has tendency to loose electron and go to +2 o.s and Br goes to -1 and Ch3 thus has tendency to gain electron and goes to Ch3-, here ch3 had tendency to take away the electrons and thus is a -I group
    Option D) No2 , here N attached to C is very electronegative and hence N02 acts as -I group and hence Ch3 acts as +I group

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Yeah but Br doesn’t form double bond by sharing its lone pair.

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Question no 1015727660783542117280384809208360

Question 121572767717797329413365842568781 answer is e why

Option e because there is no way he can donate electron.

Please tell by drawing the structures

What you have done is, you have only taken into consideration the inductive effect , but
OH is a +M group and hence it is electron donating group
Also OCH3 is a +M group
But SO3H is a -M group
image

Question 10 I’m getting 5 resonating structures

Yes there are 5 please show all

image
For count resonating structures of this type of structure , always rotate double bond across one ring at a time

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@abhijit_2020
image
you can also try these out and you can even remember these because in some easy exams these questions do come directly.

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Ya all these examples given by you was given as homework to draw resonating structures by our sir

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Question no 14 please tell how resonance will take place in a and b compounds by showing and in question 18 i think d is correct answer but c is given as answer 15728699515188141786136596239065

See in question 14 resonance will occur in option A (+)charge will do resonance with benzene ring.
In option B resonance will under go with adjacent pie bond.

Q18 ) for pie bond conjugation pie bonds should be at alternative C and hence a and b can’t be correct , only option c is correct

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