Question no 4,6 and 8
Please Confirm these answers
Ch3Mgbr , Ch3-mg(2+)--br
Triple bond is more electronegative than double bond so that’s why in b option phenyl +I first a is simple -I :
For question 8 option C because it has lone pair to donate. So it’s donating group.
CH3 has sp3 C,which is less electronegative than sp2 C of benzene ring, so it show +I effect.
-CCH has sp C ehich is more e.n. than sp2 C, so it shows -I effect.
Also, Br also has 3 lp, but in case of halogens -I effect dominates over +M effect.
Option A) Cl is very electronegative and hence it will act as -I group and hence Ch3 will act as +I group
Option B) No electronegativity difference
Option C) It is a famous reagent known as grignard reagent , there Mg being a metal has tendency to loose electron and go to +2 o.s and Br goes to -1 and Ch3 thus has tendency to gain electron and goes to Ch3-, here ch3 had tendency to take away the electrons and thus is a -I group
Option D) No2 , here N attached to C is very electronegative and hence N02 acts as -I group and hence Ch3 acts as +I group
Yeah but Br doesn’t form double bond by sharing its lone pair.
Question no 10
Question 12 answer is e why
Option e because there is no way he can donate electron.
Please tell by drawing the structures
What you have done is, you have only taken into consideration the inductive effect , but
OH is a +M group and hence it is electron donating group
Also OCH3 is a +M group
But SO3H is a -M group
Question 10 I’m getting 5 resonating structures
Yes there are 5 please show all
For count resonating structures of this type of structure , always rotate double bond across one ring at a time
you can also try these out and you can even remember these because in some easy exams these questions do come directly.
Ya all these examples given by you was given as homework to draw resonating structures by our sir
Question no 14 please tell how resonance will take place in a and b compounds by showing and in question 18 i think d is correct answer but c is given as answer
See in question 14 resonance will occur in option A (+)charge will do resonance with benzene ring.
In option B resonance will under go with adjacent pie bond.
Q18 ) for pie bond conjugation pie bonds should be at alternative C and hence a and b can’t be correct , only option c is correct