P+an²/v2 so higher than ideal gas
The pressure when low, molecules are far apart from one another, so no attractive or repulsive behaviour seen. While when high pressure, they behave like van der waals as they will be closer to one another and exhert forces on each other.
But see this
Oh. I was conceptually wrong. Sorry for it.
See this quora answer, it might clarify.
Answer is incorrect then.
Yes D is correct. Checked with FIITJEE archive.
See basically if a real gas has a pressure P, then for ideal gas the pressure lost due to molecular interactions in a real gas should be added. So pressure in a ideal gas will be P+pressure lost by molecular interactions. Hope you got it!