Doubt from functions

1562330579027265974903
Q10
Answer is A


Do ask if any doubts

Why haven't you considered the case when sin(sin(x²)) =1.. which will give x= ROOT((2n+1)pi/2) It's not given in options but still it can be a soln??

Bro when sin (sinx^2)=1 then sin x^2=2npi+pi/2
But -1 <sin x <1 and even if n=0 sin x^2 will be equal to pi/2 (>1) ,which is not possible.
@Saumay_2019

Oh yes..got it