Doubt from Elimination Reactions

Why is the same conjugate acid of the alkoxide ion used as solvent in E2 Elimination reactions ?
Like NaOCH3 with CH3OH...
And Sodium Ethoxide with Ethanol...?

As a base

Please be clear. Everyone knows that a Base is required for elimination reactions and alkoxide ion is the base here..
My question was why the 'specific' pair of the Sodium Alkoxide and Alkanol (conjugate) solvent is used 'together'...

It is not necessary

But in majority of case we use it , because to make sure any other acid base reaction doesn't takes place.

So we may use Sodium Methoxide with Ethanol as solvent, right ?

Yes you can
But sodium methoxide try to do acid base reaction with ethanol .

Can you please elaborate... What acid-base reaction between Methoxide ion and Ethanol are you talking about ?

Ethoxide formation and methanol formation

You get it?

Isn't Methoxide ion the weaker base as compared to Ethoxide ?
How will it replace 'H+' from Ethanol then ?

Are yaar
Agar stronger base nhi h to reaction nhi hoga.
Then you can use it without any complications.
I just want to say if you are mixing two different types of solvent and its alkoxide ion then you can check acid base reaction

Further if acid base reaction happen then it will give any effect of outcome of reaction.

Outcome of reaction will not affected by solvent that you use until you stop getting very strong base and strong base don't get utilitie by any other thing.