Yes how @Anindya_Sikdar
Why u took x=R+y not getting @Anindya_Sikdar @pratyaksh_tyagi
Y is very small. So its assumed the E is uniform for the length y. Anyways I should have written R.
7-D. ? @Aayush
-q charge will be induced on the surface
Wait tell me the basics of induction. @pratyaksh_tyagi
What will be the distribution? How to do induction
As field is zero in shell. So apply gauss law . Q enclosed will be 0 , therefore a same magnitude but opposite sign charge must induce.
Yes that gauss thing i know but what about distribution?
also give me the link of that question jisme ek circular cross section hota hai jiska radius linearly badhta hai..ok and resistance nikalni hoti hai @pratyaksh_tyagi
You solved it here.
Distribution will Be uniformly over the surface @Aayush it is independent of the position of the charge inside
I don't Remember the question you re saying
Yes then how u calc field without knowing distribution? @pratyaksh_tyagi
It will be uniform only bro
Here I ask 'Why' ? @pratyaksh_tyagi
I am asking the question in which there is hollow cylinder and its radius increases from a \rightarrow b linearly and we are supposed to find its resistance.
Don't know a good reason.
Not able to understand the resistance question @Aayush elaborate a bit . Or send printed version
Sorry i dont have the question. @pratyaksh_tyagi
But see this pic I found on google.
Now got it?