Ohh I didnt notice the negative sign.
@Anindya_Sikdar which test series is this?? I mean of which institution
Which que of #65?
R, forgot to mention
Yeah, even I thought it would work. But its giving double the answer right?
Yup getting -0.36V even after taking proper electron change
And getting -0.18 by just adding them
Yes bro. Getting same.
Considering only H2 gives the answer I think they are assuming something else like h2s2o8 is forming at anode but imo it's wrong.
Shouldn't it be like this
Moles of electrons transfer = 1200/96500 =a
So moles of electrons = n ?
How do we calculate n here ? I guess it is H2 and O2 so it may be 4a/6 ?
Is it correct @Chirag_Hegde @Viraam_Rao
V = n×0.0821×300/1
What I had done was find the number of moles of H2 and O2 separately
N factor of H2 here is 2
And O2 is 4
ND then add them
Please help me clear my concepts, thanks in advance!
This is not in syllabus
Involves transport number
I can send you the cengage solution if you want but time waste hai
Sure right? Not chance of it coming as paragraph type?
Can you just upload once? I want to see it.
But these are general doubts from electrochemistry, can you clear these?
And yes please post the solution also
We deside it by discharge potential ( negative of Srp value)
Lowest discharge potential is favoured