Cd----->Cd^2+ + 2e
Na^+ + e-------> Na ×2
We will get the cell reaction as,
Cd+2Na^+--------> Cd^2+ + 2Na.
i dont think this will be it coz a single half cell is given, and using this how will we find ksp of Cd(OH)2?
You had asked for the cell reaction, I posted it.
If you need to find Ksp then go on the basis of half cell reactions as done in ionic.
can you show the solution please?