# Doubt from differential equations

**pushkar_2020**#1

**Hari_Shankar**#5

Let x=r,y=\cos \theta

you can rewrite as -xdy+(x^3-2x^2y+y) dx =0

or \dfrac{dy}{dx}+ y(2x - \dfrac{1}{x})=x^2 which is a linear form.

The soln will be ye^{x^2}=\dfrac{x}{2} e^{x^2} (x^2-1)

2 Likes