I have written the same in my notes . exact reason I don't know
How 0 unpaired in second? Can you show the config please?
SE says Fe has OS of +3 in brown ring complex?
Yeah bro. They say +3 and -1
Well it will be in future for sure ( jee will include it too ) ( that's my sir said)
Why 0 in 2nd structure tho please explain bro
All get paired.
Ah right was making a mistake
Then What will be hybridization of second ??
d2sp3 I guess.
There will be 8 valence e^- .. so two e^- from s must come in d orbital to empty s shell to make it available for e^- donation
So if they come in d orbital then how 2 d orbital can undergo hybridisation(it will have 8 e^-)
I thought the 2s electrons will go into a p orbital. Saying this just cuz the ligands are strong.
If it forms d2sp3
Two e- will have to go in other higher orbit ..
So is it strong much to do that
Maybe the complex they gave is wrong. Maybe its the sodium nitroprusside wala anion.
Whats the answer?
@Chirag_Hegde bro well u r right 8 but additional 5 pairs of electrons due to CO. ( they r asking at metal centre.)
Yes but valence shell is 4s2 4p6 right bro?
Why are they counting 3d10
That was my doubt
As oxidation number of metal increases it's pie bond formation tendency decreases so M-C bond strength decreases and C-O bond strength increases. So C is correct and D seems to be wrong
Why that trend tho?