Doubt from Chemical/Ionic Equilibrium


Answer 2B
7C

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For 2 I'm getting 4.6
Is the solution given?

Nope.What volume or concentration are you taking for 2?

Just writing simultaneous equilibriums
R1-oh+ ch3cooh<=>ch3cooR1
1-X. 1-(X+Y. ) X
Similar for r2-oh
X+y=0.8
And x/y=3/2
Then find k1=x/(1-x)(1-(x+y))

But we can't assume concentration of x and y as 1.They have given only moles I think some data is missing in question

Anyone?

@Ayan_Agrawal it is written that "2 moles of an equilmolar mixture" so conc of alcohols can be taken 1. I got the same ans as chirag

https://books.google.co.in/books?id=nJKKBAAAQBAJ&pg=SA5-PA41&lpg=SA5-PA41&dq=Two+moles+of+an+equimolar+mixture+of+two+alcohols+r1-oh+and+r2-oh+are+esterified+with+1+mole+of+acetic+acid.&source=bl&ots=OoOW_Gy-WR&sig=ACfU3U12NOzns3yNxZ4zJkoqyOgS7Vuz2Q&hl=en&sa=X&ved=2ahUKEwjf8Lv4kajiAhVP4nMBHajQBqQQ6AEwBXoECAkQAQ#v=onepage&q=Two%20moles%20of%20an%20equimolar%20mixture%20of%20two%20alcohols%20r1-oh%20and%20r2-oh%20are%20esterified%20with%201%20mole%20of%20acetic%20acid.&f=false

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Okk got it. They had considered water also

@chetan_pandey
I considered water and got 2.21.
Are you getting B?


See their solution
No firstly i was getting 4.6 but after considering it is coming 3.69

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@chetan_pandey
Ohh I forgot to take x+y for water. THANKS

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