For 2 I'm getting 4.6
Is the solution given?
Nope.What volume or concentration are you taking for 2?
Just writing simultaneous equilibriums
1-X. 1-(X+Y. ) X
Similar for r2-oh
Then find k1=x/(1-x)(1-(x+y))
But we can't assume concentration of x and y as 1.They have given only moles I think some data is missing in question
@Ayan_Agrawal it is written that "2 moles of an equilmolar mixture" so conc of alcohols can be taken 1. I got the same ans as chirag
Okk got it. They had considered water also
I considered water and got 2.21.
Are you getting B?
Ohh I forgot to take x+y for water. THANKS