Hmm Kc is so high!!! First time seeing. i doubt if an eqb will be established even... I think it'll proceed towards completion. Even if an eqb is established it would be for a very very short time. So I think it should be 0.4 0 0.2 as Br2 is the limiting reagent.
When kc is very high, take the full reaction forward first consuming the Limiting reagent. Then bring it back ( 0.4- alpha) then you can make approximations of \alpha \rightarrow 0
@pratyaksh_tyagi is my answer correct?
@seshu_ram your answer is incomplete, it will again form an equilibria of HBr.
Vaise mera bhi answer yahi tha pehli baar
Mera doubt yahi tha ki hum dobara equilibria wala answer batayenge ya pehle wala
Second eqb? I don’t get it? How is the second equilibrium established?
May be this will help you
Bro this eqb how do you expect it to be established as well? Kc has to be 2*10^-9
There will be very small amount of br2 at equilibrium
I guess they are both the steps of the solution !
First write K_c equation and then use K_p = K_c ×RT