Ohh ok then @Ishita_Anand KIE reason for aldol is perfect then.
But what about Cannizzaro. I feel even Cannizzaro will show KIE.
Sis, this isn't KIE afaik. This is just isotopic exchange.
KIE is if alpha hydrogens where replaced by D then how would the rate change.
ohhhh i thought they must be same
you said if kie is alpha hydrogen gets replaced right ?
but benzaldehyde mai toh alpha hydrogen h hi nhin. Then why would go for aldol ?
Answer is ac
[/quote="Supreeta_Sen, post:21, topic:41373"]
Extraction of hydrogen by OH
No the second step is RDS
No no. See we started discussion with Cannizzaro. I asked you if these two will have same rate
Ph COD and Ph COH.
Thats KIE. They wont have same rate cuz in RDS CD or CH bond is to be broken and the ease of breaking will be different.
I got it, Breaking of C-D bond isnt the RDS in canixaro.
Why it can't be B, as OD- will attack the carbonyl
Arghhhhh !! everything in my head got muddled up
@Viraam_Rao i will re-read and understand once again
I actually didnt get both B and C.
Lets wait for @Supreeta_Sen @Ishita_Anand
Shouldn't B give only PhCH2OD
Now in C how is there D in the alcohol ?
I am getting Ph CHD OD for C.
Not getting where that Ph CD2 OD is coming from .
@Viraam_Rao option C
Thanks. I was transferring the deuteuride to PhCOH only.
Even this is possible right.
Thnks, in a option why dioxoanion is formed
Yes, sure. But in the question since they specifically mentioned their own compound, you gotta self aldol that one only I think
@pratyaksh_tyagi no prob
thanks. was doing same mistake as @Viraam_Rao
True. I meant it didnt even strike me that I CAN transfer the D- to PhCOD itself. LOL.
See a option
That excess base will pull out another H from OH?
Yes, that's what my notes say about the oxoanion.
The reaction order also changes, from 3 to 4.
3 for usual cannizaro, 4 for the oxoanion one.